在此示例中，Regexp在white-space之后匹配

Question

/.n/g matches "nope, an apple is on the tree"

Notice that the ' n ' of ' nope ' is unaffected because:

(The decimal point) matches any single character except the
newline characters: \n \r \u2028 or \u2029. ([\s\S] can be
used to match any character including newlines.)

https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/RegExp

.

But the problem is that I do NOT want to match the 'n' that comes after a white-space:

/.n/g matches "I don't want to match this n !"

How can I achieve this?

Answer 1

A regexp like /[\\S]n/g (or the shorter, less readable, version /\\Sn/g will provide you with the functionality you asked for. \\S will match any character that isn't a whitespace.

Remember that \\S will not match " " , "\\t" , etc. if you just want to ignore "real" spaces /[^ ]n/g is the way to go.

Answer 2

Although javascript regexps derive from Perl, they do not implement conditional matching and lookarounds. I believe, your only option is to exclude the whitespace family as @refp and @TudorConstantin have already suggested: /\\Sn/g .

Answer 3

请尝试使用排除空格族的字符类：

/[\S]n/g