在Python脚本中使用“apt-get install xxx”

Question

currently I need to install some package using apt or rpm, according the OS. I saw the lib "apt" to update or upgrade the system, but it is possible use it to install a single package?

I was trying to use too "subprocess":

subprocess.Popen('apt-get install -y filetoinstall', shell=True, stdin=None, stdout=None, stderr=None, executable="/bin/bash")

But this command shows all process in the shell, I cannot hide it.

Thank you for your help.

Answer 1

You can use check_call from the subprocess library.

from subprocess import STDOUT, check_call
import os
check_call(['apt-get', 'install', '-y', 'filetoinstall'],
     stdout=open(os.devnull,'wb'), stderr=STDOUT) 

Dump the stdout to /dev/null , or os.devnull in this case.

os.devnull is platform independent, and will return /dev/null on POSIX and nul on Windows (which is not relevant since you're using apt-get but, still good to know :) )

Answer 2

Thank guys ! I use part of each solution. My code:

proc = subprocess.Popen('apt-get install -y FILE', shell=True, stdin=None, stdout=open(os.devnull,"wb"), stderr=STDOUT, executable="/bin/bash")
proc.wait()

Added: stdout and .wait

Thank you one more time from Argentina !

Answer 3

对于这个特定的任务，作为subprocess的替代方案，您可以考虑使用Fabric ，这是一个自动化构建的python部署工具。

Answer 4

Use this to redirect the output to /dev/null:

proc = subprocess.Popen('apt-get install -y filetoinstall', shell=True, stdin=None, stdout=open("/dev/null", "w"), stderr=None, executable="/bin/bash")
proc.wait()

The call to .wait() will block until the apt-get is complete.