[英]How do I move a relative symbolic link?
I have a lot of relative symbolic links that I want to move to another directory.我有很多我想移动到另一个目录的相对符号链接。
How can I move symbolic links (those with a relative path) while preserving the right path?如何在保留正确路径的同时移动符号链接(具有相对路径的链接)?
You can turn relative paths into full paths using readlink -f foo
.您可以使用readlink -f foo
将相对路径转换为完整路径。 So you would do something like:所以你会做这样的事情:
ln -s $(readlink -f $origlink) $newlink
rm $origlink
EDIT:编辑:
I noticed that you wish to keep the paths relative.我注意到您希望保持路径相对。 In this case, after you move the link, you can use symlinks -c
to convert the absolute paths back into relative paths.在这种情况下,移动链接后,您可以使用symlinks -c
将绝对路径转换回相对路径。
This is a perl
solution that preserves relative paths:这是一个保留相对路径的perl
解决方案:
use strictures;
use File::Copy qw(mv);
use Getopt::Long qw(GetOptions);
use Path::Class qw(file);
use autodie qw(:all GetOptions mv);
my $target;
GetOptions('target-directory=s' => \$target);
die "$0 -t target_dir symlink1 symlink2 symlink3\n" unless $target && -d $target;
for (@ARGV) {
unless (-l $_) {
warn "$_ is not a symlink\n";
next;
}
my $newlink = file(readlink $_)->relative($target)->stringify;
unlink $_;
symlink $newlink, $_;
mv $_, $target;
}
One can use tar
to move a folder containing relative symbolic links.可以使用tar
移动包含相对符号链接的文件夹。
For example:例如:
cd folder_to_move/..
tar czvf files.tgz folder_to_move
cd dest_folder/..
tar xzvf /absolute/path/to/folder_to_move/../files.tgz
# If all is fine, clean-up
rm /absolute/path/to/folder_to_move/../files.tgz
rm -rf /absolute/path/to/folder_to_move
Improving on Christopher Neylan's answer:改进 Christopher Neylan 的回答:
~/bin $ cat mv_ln
#!/bin/bash
#
# inspired by https://stackoverflow.com/questions/8523159/how-do-i-move-a-relative-symbolic-link#8523293
# by Christopher Neylan
help() {
echo 'usage: mv_ln src_ln dest_dir'
echo ' mv_ln --help'
echo
echo ' Move the symbolic link src_ln into dest_dir while'
echo ' keeping it relative'
exit 1
}
[ "$1" == "--help" ] || [ ! -L "$1" ] || [ ! -d "$2" ] && help
set -e # exit on error
orig_link="$1"
orig_name=$( basename "$orig_link" )
orig_dest=$( readlink -f "$orig_link" )
dest_dir="$2"
ln -r -s "$orig_dest" "$dest_dir/$orig_name"
rm "$orig_link"
This is also part of https://github.com/tpo/little_shell_scripts这也是https://github.com/tpo/little_shell_scripts 的一部分
Use ln
of course:当然使用ln
:
for i in *; do # or whatever pattern you're wanting to match
ln -sr "$(readlink "$i")" newdir/"$i";
done;
I was surprised this works, but LN(1)
must be smart enough to take note of what's going on and help you out!我很惊讶这行得通,但LN(1)
必须足够聪明才能注意到正在发生的事情并帮助你! I even tried it with a "newdir" of ../somethingelse
(which should be a no-op in the link re-writing) and ..
(which will remove a ..
from the link target), and it worked wonderfully.我什至用../somethingelse
的“newdir”(这应该是链接重写中的无操作)和..
(这将从链接目标中删除..
来尝试它,并且它工作得非常好。
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