[英]How to ignore regex matches wrapped by a particular string?
Long time lurker, first time poster- please bare with me, I'm a regular expression n00b, but I had a great idea for some functionality on a project and I've tried to implement it to the best of my ability but I need a little help achieving the desired effect. 很长一段时间潜伏,第一次海报 - 请光临我,我是一个正则表达式n00b,但我对一个项目的某些功能有一个好主意,我试图尽我所能实现它但我需要一点帮助达到预期的效果。 The page in question is: http://dev.favorcollective.com/guidelines/ (just to provide some context)
有问题的页面是: http : //dev.favorcollective.com/guidelines/ (仅提供一些上下文)
I'm using php's preg_replace to go through a particular page's contents (giant string) and I'm having it search for glossary terms and then I wrap the terms with a bit of html that enables dynamic glossary definition tooltips. 我正在使用php的preg_replace来浏览特定页面的内容(巨型字符串),并让它搜索词汇表术语,然后用一些html包装这些术语,以启用动态词汇表定义工具提示。
Here is my current code: 这是我目前的代码:
function annotate($content)
{
global $glossary_terms;
$search = array();
$replace = array();
$count=1;
foreach ($glossary_terms as $term):
array_push($search,'/\b('.preg_quote($term['term'],'/').')[?=a-zA-Z]*/i');
$id = "annotation-".$count;
$replacement = '<a href="'.get_bloginfo('url').'/glossary#'.preg_replace( '/\s+/', '', $term['term']).'" class="annotation" rel="'.$id.'">'.$term['term'].'</a><span id="'.$id.'" style="display:none;"><span class="term">'.$term['term'].'</span><span class="definition">'.$term['def'].'</span></span>';
array_push($replace,(string)$replacement);
$count++;
endforeach;
return preg_replace($search, $replace, $content);
}
• But what if I want to ignore matches inside of <h#> </h#> tags? •但是,如果我想忽略<h#> </ h#>标记内的匹配怎么办?
• I also have a particular string that I do not want a specific term to match within. •我也有一个特定的字符串,我不想在其中匹配特定的术语。 For example, I want the word "proficiency" to match any time it is NOT used in the context of "ACTFL Proficiency Guidelines" how would I go about adding exceptions to my regular expression?
例如,我想在“ACTFL熟练度指南”的上下文中使用“熟练度”这个词来匹配任何时候我如何在正则表达式中添加例外? Is that even an option?
这甚至是一种选择吗?
• Finally, how can I return the matched text as a variable? •最后,如何将匹配的文本作为变量返回? Currently when I match for a term ending in 's' or 'ing' (on purpose) my script prints the matched term rather than the original string that was matched (ie it's replacing "descriptions" with "description").
目前,当我匹配以's'或'ing'结尾的术语(故意)时,我的脚本打印匹配的术语而不是匹配的原始字符串(即它将“描述”替换为“描述”)。 Is there anyway to do that?
反正有吗?
Thanks! 谢谢!
not a php guy (c#), but here goes. 不是一个PHP家伙(C#),但是这里走了。 I assume that:
我认为:
'/\\b('.preg_quote($term['term'],'/').')[?=a-zA-Z]*/i'
will map to this far more readable pattern: '/\\b('.preg_quote($term['term'],'/').')[?=a-zA-Z]*/i'
将映射到这个更具可读性的模式:
/\b(ESCAPED_TERM)[?=a-zA-Z]*/i
so, as far as excluding <h#> type tags, regex is ok only if you can assume your data would be the simple, non-nested case: <h#>TERM<h#>. 因此,只要排除<h#>类型标记,只有当您可以假设您的数据是简单的非嵌套情况时,正则表达式才可以:<h#> TERM <h#>。 If you can, you can use a negative lookahead assertion:
如果可以,您可以使用负前瞻断言:
/\b(ESCAPED_TERM)(?!<h\d>)[?=a-zA-Z]*/i
you can use a lookahead with a lookbehind to handle your special case: 你可以使用带有lookbehind的前瞻来处理你的特殊情况:
/\b(ESCAPED_TERM|(?<!ACTFL )Proficiency(?!\sGuidelines))(?!<h\d>)[?=a-zA-Z]*/i
note: if you have a bunch of these special cases, PHP might (should) have an "ignore whitespace" flag which will let you put each token on newline. 注意:如果你有一堆这些特殊情况,PHP可能(应该)有一个“忽略空格”标志,它可以让你将每个标记放在换行符上。
Regular expressions are awesome, wonderful, magical. 正则表达式很棒,很棒,很神奇。 But everything has its limits.
但是,一切都有其局限性。
That's why it's nice to have a language like PHP to provide the extra functionality. 这就是为什么拥有像PHP这样的语言来提供额外功能的原因。 :)
:)
Can you strip out headers with a non-greedy regexp? 你能用非贪婪的正则表达式删除标题吗?
$content = preg_replace('/<h[1-6]>.*?<\/h[1-6]>/sim', "", $content);
If non-greedy evaluations aren't working, what about just assuming that there won't be any other HTML inside your headers? 如果非贪婪的评估不起作用,那么假设你的标题中没有任何其他HTML呢?
$content = preg_replace('/<h[1-6]>[^<]*<\/h[1-6]>/im', "", $content);
Also, you might want to use sprintf to simplify your replacement: 此外,您可能希望使用sprintf来简化替换:
/*
1 get_bloginfo('url')
2 preg_replace( '/\s+/', '', $term['term']).
3 $id
4 $term['term']
5 $term['def']
*/
$rfmt = '<a href="%1$s/glossary#%2$s" class="annotation" rel="%3$s">%4$s</a><span id="%3$s" style="display:none;"><span class="term">%4$s</span><span class="definition">%5$s</span></span>';
...
$replacement = sprintf($rfmt, get_bloginfo('url'), preg_replace( '/\s+/', '', $term['term']), $id, $term['term'], $term['def'] );
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