[英]How to get the size of a template argument when using CRTP?
In VC++10 the following example fails with error C2027: "use of undefined type 'X'". 在VC ++ 10中,以下示例失败,错误为C2027:“使用未定义的类型'X'”。 However g++ 4.6 compiles it just fine.
但是,g ++ 4.6可以很好地进行编译。
template<class T>
class C
{
static const size_t size = sizeof(T);
};
class X : public C<X> { };
So which one is right? 那么哪一个是对的? And how would I do this so that it works on mainstream compilers?
我将如何做才能使其在主流编译器上运行?
It's not a huge deal though, cause VC++ still allows sizeof(T) inside member functions of C. I just have to repeat some long type definitions which is annoying. 不过,这并不是什么大问题,因为VC ++仍允许C的成员函数内使用sizeof(T)。我只需要重复一些很烦人的长类型定义即可。
EDIT: I realize my example was bad because what I really wanted to do was to use the size as a compile time constant, in this way: 编辑:我意识到我的例子很糟糕,因为我真正想做的就是以这种方式使用大小作为编译时间常数:
template<size_t size> class C2 { };
template<class T>
class C
{
typedef C2<sizeof(T)> A;
};
class X : public C<X> { };
Both compilers reject this so I assume it's probably not possible, but like I said I can still use sizeof inside functions. 两个编译器都拒绝这样做,所以我认为这可能是不可能的,但是就像我说的那样,我仍然可以在函数内部使用sizeof。 I was just hoping I wouldn't have to repeat the typedef inside every function.
我只是希望我不必在每个函数中重复typedef。
template<size_t size> class C2 { };
template<class T>
class C
{
void foo() { typedef C2<sizeof(T)> A; }
};
class X : public C<X> { };
The static member cannot be initialized in the class itself, because the type T
is being defined, and is not complete yet. 静态成员不能在类本身中初始化,因为类型
T
正在定义中,并且尚未完成。
However, you can initialize it outside the class as: 但是,您可以在类外部将其初始化为:
template<class T>
class C
{
static const size_t size;
};
template<typename T>
const size_t C<T>::size = sizeof(T); //initialization of the static member
It should compile fine: http://ideone.com/6sNgN 它应该可以正常编译: http : //ideone.com/6sNgN
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