在控制台中使用Firebug打印元素名称

Question

I want to listing all input elements in console of firebug so in console window write the followings:

var inputs = $(":input");
console.log(inputs);

but when I press the Run in console appear null

also when I write just var inputs = $(":input"); the console show Undefined I sure the page have a lot of input elements, where is the problem?

Answer 1

There is nothing wrong with the provided snippet.

Though, without specifying what to write (using console.log ) firebug will print whatever the last statement returned, when declaring a variable using var the result is always undefined .

var inputs = $(":input"); // firebug printing 'undefined' is valid
var abc = 123;            // results in the same thing

---

Please make sure that the website in question actually uses jQuery (bound to global $ ), and that there really are input elements present in the DOM.

Also make sure that the jQuery version running is of a version later/equal to 1.0 ( :input selector didn't exists until then).

If it has jQuery it probably is of a more recent version, how ever; without you providing us with additional information there is no way to guarantee it.

Answer 2

simply go to the firebug console and wrtie as @refp mentioned the page in question must have jquery included

 $(":input")

press run