如何编写一个查询，该查询为一个列中的每个不同值返回一行，并从另一列中返回一个任意值？

Question

I'd like to find a, hopefully simple, solution to the following problem.

I have a table like this

Name -  GUID 

NameA   {AH42-AJG5-AFHA}      
NameA   {AJD4-AFJ4-HVFA}      
NameB   {BGA4-AJGA-GHAA}
NameB   {JGA8-GGK1-KLP9}      
NameA   {KGA4-JAD4-GJA9}

An example of my desired outcome is

NameA   {AH42-AJG5-AFHA} 
NameB   {BGA4-AJGA-GHAA}

I want exactly 1 entry for a specific name, and I need any GUID which was associated with this name in the second column. (The GUID that is returned is arbitrary)

Thanks for your advice.

Answer 1

Assuming what GUID is returned is irrelevant; so long as it has an Associate to one of the names.

Select [name], min([GUID]) as mGuid
FROM tableLikeThis
Group by [Name]

Answer 2

Just to mention an alternate way of doing it (xQbert already answered the question). You could do something along:

SELECT DISTINCT ON (Guid) Name, Guid  
FROM Table