如何使用正则表达式获取字符串的一部分？

Question

this is my string: http://www.something.com/path/tt 0425235 /somethingelse/

and i need to get just "0425235" (Beetween "tt" and "/")

Test with:http://rubular.com/

Answer 1

#http://www\.imdb\.com/title/tt(\d+)/#

Answer 2

Simple and perfect ;)

<?php
$match = array();
$url = 'http://www.something.com/path/tt0425235/somethingelse/bla/bla/bla/bla/?bla=bla';
preg_match( '/\/path\/([a-z]+([\d]+))+\/?/i' , $url , $match );
print_r( $match );
?>

Bye!

Answer 3

$url = 'http://www.something.com/path/tt0425235/';

list($id) = preg_split('~^.*/tt(\d+)/$~', $url, 2, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY) + array(NULL);

If it can't find your pattern, $id will be NULL .

Answer 4

/http:\/\/[\w+-_\.]+\/path\/tt(\d+)\//

要么

~http://[\w+-_\.]+/path/tt(\d+)/~