CodeIgniter表单操作网址变量

Question

What would be the exact CodeIGniter format to the below form tag. 以下表单标签的确切CodeIGniter格式是什么？ Thanks 谢谢

    <form action="links/link1.php?view=one" method="post">

Will this work 这项工作会吗

        echo form_open('links/link1.php?view=one');

Answer 1

That's right. 那就对了。

echo form_open('links/link1.php?view=one');

will create a form similar to this: 将创建类似于以下形式：

<form action="links/link1.php?view=one" method="post">

Hope this helps. 希望这可以帮助。