[英]How to sort an array in JavaScript
I am not using an associative array. 我没有使用关联数组。 I'm using 1d array like this,
我正在使用像这样的1d数组,
array("1,a","5,b","2,c","8,d","6,f");
How can I sort this array? 我该如何排序这个数组?
The result should be, 结果应该是,
array("1,a","2,c","5,b","6,f","8,d");
sort()
without a custom sorting function will sort it how you wish (lexicographically). 没有自定义排序功能的
sort()
将按照您的意愿(按字典顺序)对其进行排序。
>>> ["1,a","5,b","2,c","8,d","6,f"].sort();
["1,a", "2,c", "5,b", "6,f", "8,d"]
Note that this will sort the original array. 请注意,这将对原始数组进行排序。 You can make a shallow copy with
slice()
. 您可以使用
slice()
创建浅表副本。
If any of your numbers are larger than 9
, and you want to sort it via the ordinal of the number, you will need a custom sorting function. 如果您的任何数字大于
9
,并且您想通过数字的序数对其进行排序,则需要自定义排序功能。
["1,a","5,b","2,c","8,d","6,f"].sort(function(a, b) {
return parseInt(a, 10) - parseInt(b, 10);
});
Use array.sort()
built-in JS function. 使用
array.sort()
内置JS函数。 Documentation here: http://www.w3schools.com/jsref/jsref_sort.asp 文档: http : //www.w3schools.com/jsref/jsref_sort.asp
Try this 试试这个
<script>
var abc=new Array("1,a","5,b","2,c","8,d","6,f");
document.write("<br/>");
document.write(abc.sort());
</script>
http://jsfiddle.net/Dht33/ http://jsfiddle.net/Dht33/
var arrayVar = ["1,a","2,c","5,b","6,f","8,d"];
arrayVar.sort()
arrayVar; // "1,a","2,c","5,b","6,f","8,d"
try with: 尝试:
function sortNumber(a,b)
{
return (a.split(","))[0] - (b.split(","))[0] ;
}
var n = ["1,a","5,b","2,c","8,d","6,f"];
alert( n.sort(sortNumber) );
Here's what I do: 这是我做的:
var arr1 = new Array("1,a","5,b","2,c","8,d","6,f");
var arr2 = arr1.sort( function(a, b){
var ax = a.split(",");
var bx = b.split(",");
return ax[0]-bx[0];
});
document.getElementById("result").innerHTML = arr2.join(" : ");
You need to write your own comparison function to compare the numbers, otherwise the default sort()
would put something like "40,a"
before "5,b"
. 你需要编写自己的比较函数来比较数字,否则默认的
sort()
会在"5,b"
之前加上类似"40,a"
东西。
Here's an example which just splits on the ,
character and assumes the value before it is numerical. 这是一个例子,它只是在字符上进行分割
,
并假定它在数值之前的值。 I've added "40,a"
into the example to show that it orders numbers >9 correctly. 我在示例中添加了
"40,a"
,表明它正确地命令数字> 9。
function mySort(a,b)
{
return a.split(",", 1) - b.split(",", 1);
}
var theArray = ["1,a", "5,b", "2,c", "40,a", "8,d", "6,f"];
theArray.sort(mySort); // "1,a","2,c","5,b","6,f","8,d","40,a"
I'm going to go ahead and assume you want to sort by the number part first, sorting numerically, and then have a secondary lexographic (string) sort on the bit after the comma. 我将继续并假设您要先按数字部分排序,按数字排序,然后在逗号后面的位上进行二级词法(字符串)排序。 That way a value like "11,a" will end up after "2,a" - if you just do a default sort "11,a" will end up before "2,a".
这样一个像“11,a”这样的值将在“2,a”之后结束 - 如果你只是做一个默认排序“11,a”将在“2,a”之前结束。 So:
所以:
var a = ["1,a","11,a","8,a","24,z","5,b","2,c","8,d","6,f"];
a.sort(function(a,b) {
var aparts = a.split(","),
bparts = b.split(","),
anum = +aparts[0], // convert first part to number
bnum = +bparts[0],
aletter = aparts[1],
bletter = bparts[1];
if (anum === bnum)
return aletter < bletter ? -1 : aletter === bletter ? 0 : -1;
else
return anum - bnum;
});
Result: 结果:
["1,a", "2,c", "5,b", "6,f", "8,a", "8,d", "11,a", "24,z"]
Try this: 试试这个:
<script type="text/javascript">
var testArray = new Array();
testArray[0] = '1';
testArray[1] = '5';
testArray[2] = '9';
testArray[3] = '8';
testArray[4] = '6';
testArray[5] = '2';
var getlength = testArray.length;
testArray.sort(function(a,b){return a - b});
for(var i=0; i<getlength;i++) {
alert(testArray[i]);
}
</script>
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