如何获得std :: numeric_limits <char> :: min（）值？

Question

How to get (correctly and/or readable value of) std::numeric_limits<char>::min() ?

cout << std::numeric_limits<char>::min() << endl;
cout << std::numeric_limits<char>::max() << endl;

return

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Answer 1

You just need to convert it to something that when streamed to cout will interpret it as an integer. Eg

#include <limits>
#include <iostream>
#include <ostream>

int main()
{
    int minc = std::numeric_limits<char>::min();
    unsigned maxc = std::numeric_limits<char>::max();

    std::cout << minc << std::endl;
    std::cout << maxc << std::endl;
}

I deliberately use unsigned for std::numeric_limits<char>::max() just in case sizeof(int) == 1 and char is unsigned.

Answer 2

The problem is that the standard streams will output char s as characters and not as integral values. You can force them to do that by casting to an integral type that isn't a character type:

cout << (int)std::numeric_limits<char>::min() << endl;
cout << (int)std::numeric_limits<char>::max() << endl;

Answer 3

Just cast it to an int .

cout << (int)std::numeric_limits<char>::min() << endl;
cout << (int)std::numeric_limits<char>::max() << endl;