将byte []转换为short []

Question

Okay, I'm trying to convert a byte[] to a short[], or Int16[].

List<Int16[]> lol = new List<Int16[]>();
byte[] b = System.Text.Encoding.Default.GetBytes("lolololololololololololoolol");
lol.Add(Convert.ToInt16(b));

MessageBox.Show(Encoding.Default.GetString(Encoding.Default.GetBytes(lol[0])));

That is something that I tried, but obviously, it doesn't work. So how would I do this?

Answer 1

It looks to me like you want to convert an entire array in one line. It could be done like this:

List<Int16[]> lol = new List<Int16[]>();
byte[] b = System.Text.Encoding.Default.GetBytes("lolololololololololololoolol");
lol.Add(Array.ConvertAll(b, x => Convert.ToInt16(x)));

Answer 2

You have to go through the byte array, and convert each element.

List<Int16[]> lol=new List<Int16[]>();
byte [] b=System.Text.Encoding.Default.GetBytes("lolololololololololololoolol");
Int16 [] a=new Int16 [b.Length];
for (Int32 i=0;i<a.Length;++i) {

    a[i]=Convert.ToInt16(b[i]);

}
lol.Add(a);

Answer 3

You probably want BitConverter.ToInt16() , which you'd need to call for each pair of bytes.

Or, use Buffer.BlockCopy to do it all at once (using the machine's native byte order).

Answer 4

        byte[] by = new byte[5];
        short[] sh = new short[5];
        by[0] = 0x1;
        by[1] = 0x2;
        by[2] = 0x3;
        by[3] = 0x4;
        by[4] = 0x5;

        for (int x = 0; x < sh.GetLength(0); x++)
        {
            sh[x] = by[x];
            MessageBox.Show(by[x].ToString());

That worked for me. Not sure if I am misunderstanding or not.