[英]Copy one string to another
I have a problem passing text to structure member. 我在将文本传递给结构成员时遇到问题。 Here is my code
这是我的代码
#include <stdio.h>
#include <string.h>
typedef struct {
char *name;
int rank;
int weapons;
}player;
player create_player(char name[], int rank, int weapons);
void display_player(player data);
int main (int argc, const char * argv[])
{
player tmp = create_player("First", 3, 3);
display_player(tmp);
}
player create_player(char name[], int rank, int weapons)
{
player newobj;
char *tmp = malloc(strlen(name) + 1);
strcpy(newobj.name, tmp);
newobj.rank = rank;
newobj.weapons = weapons;
free(tmp);
return newobj;
}
void display_player(player data)
{
printf("Player name %s\n", data.name);
printf("Player rang %d\n", data.rank);
printf("Player weapons %d", data.weapons);
}
And here is the output 这是输出
Player name
Player rang 3
Player weapons 3
As you can see the result of "Player name" is empty. 如您所见,“玩家名称”的结果为空。 Also can you give me more elegant way to asign text to newobj.name ?
还可以给我一种更优雅的方式将文本分配给newobj.name吗? What I miss ?
我想念什么?
The strcpy
in your code is wrong (it copies uninitialized data into unallocated memory). 您代码中的
strcpy
错误(它将未初始化的数据复制到未分配的内存中)。 You probably want: 您可能想要:
newobj.name = malloc(strlen(name) + 1);
strcpy(newobj.name, name);
Or more simply, if you have strdup
: 更简单地说,如果您有
strdup
:
newobj.name = strdup(name);
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