为什么不能在Python的TRY块中使用IF语句，如果可能的话，这是不错的做法？

Question

I am getting an indentation error, but my code is indented properly. If I take out the if statement, the code will run fine. Here is the relevant snippet:

 80     try:
 81         votes_a = breakdown[0]['count']
 82
 83         if breakdown[0]['pick'] != m.home:
 84            votes_b = votes_a
 85     except IndexError:
 86         votes_a = 0.0

If I remove lines 83 and 84 the code will work. Is it not possible/advisable to have control statements within try/except blocks of python code?

cheers

Update: The indentation error was not in the line that django told me, it was the line above. And, yes, there was one tab thrown in there instead of a space. Thanks.

Answer 1

Of course it's possible. If you get indentation errors, but indentation looks good visually, there's a good chance you've mixed tabs with spaces. It's best to not use tabs at all. You can run Python with -tt to detect inconsistent tab usage.

Answer 2

Python 2.7.2 (default, Jun 12 2011, 15:08:59) [MSC v.1500 32 bit (Intel)] on win
32
Type "help", "copyright", "credits" or "license" for more information.
>>> breakdown = []
>>> breakdown.append({'count':5, 'pick':0})
>>> abc = 0
>>> try:
...     votes_a = breakdown[0]['count']
...     if breakdown[0]['pick'] != abc:
...             votes_b = votes_a
... except IndexError:
...     votes_a = 0.0
...
>>> print votes_a
5
>>>

As it seems, the code itself is fine. You must've messed up spaces/tabs somewhere