[英]Regex to find alphanumeric match with day part of datetime
I have to match string like "DAY1","DAY2","DAY3"....."DAY31"
with regex in vb.net. 我必须在vb.net "DAY1","DAY2","DAY3"....."DAY31"
正则表达式匹配字符串"DAY1","DAY2","DAY3"....."DAY31"
。 I tried something like this - ^?DAY(0[1-9]|[12][0-9]|3[01])$
but it did not work. 我尝试过类似的操作- ^?DAY(0[1-9]|[12][0-9]|3[01])$
但没有用。 Please help. 请帮忙。
The pattern should have succesfull match if the source string is either DAY1
or DAY2
or DAY3
to DAY31
like so. 图案应当具有succesfull匹配如果源串或者是DAY1
或DAY2
或DAY3
到DAY31
像这样。
尝试使用以下正则表达式(删除第一个数字前的?
和0
):
^DAY([1-9]|[12][0-9]|3[01])$
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