如何通过id获取原始资源文件名？

Question

我在 res/raw 中有 .ogg 文件，我已经实现了将文件保存到 sdcard 的功能，我想从原始文件设置文件名。

Answer 1

它应该与resources.getResourceName() 一起使用；

Answer 2

使用Resources.getResourceName(id)获取package:type/entryname ，或Resources.getResourceEntryName(id)获取条目名称（文件名）。

Answer 3

If you're looking for the name from a resource ID, you can use Resources.getResourceName() . You can get the Resources object using Context.getResources() .

Personally, I'd rather store an array of strings in your strings.xml and map that to the resource IDs, but it depends on what you're really trying to accomplish.

Answer 4

This is a very old question, but in case others are trying to do the same thing, this worked for getting the filename:

Resources myResources = context.getResources();

String myFileName = myResources.getString((int)R.raw.myFile);

For some reason, even though R.raw.myFile is of the type: "final int" and Resources.getString() takes parameter "int id",

if you don't cast R.raw.myFile to int, Lint will flag the line with the error "Expected resource of type string"

Although looking through the documentation, there doesn't seem to be an overloaded version of Resources.getString() that takes a string parameter.

I am on Android Studio v3.6.3, supporting a minimum SDK of 21.