如何在我自己的应用程序中的Explore中创建“打开方式”列表

Question

In my application the user can select reference to file, for example a image file. I would like to make button with a arrow that opens a list with the programs installed on the system witch can open this file type.

I know that I can get the program names from the registry "HKEY_CURRENT_USER\\Software\\Microsoft\\Windows\\CurrentVersion\\Explorer\\FileExts", but how can I filter the entries out that have no meaning - "DllHost.exe, miaui.exe, etc." And how can I open the file with program that the user choose?

@ Lars Tech If I look in registry "HKEY_CURRENT_USER\\Software\\Microsoft\\Windows\\CurrentVersion\\Explorer\\FileExts\\" and then "OpenWithList" for the extension ".jpg" I see more entries that if if rigt click on jpg file and choose Open With ( see my first images) and I only want those. And yes there is program's entries that I properly self have added, but that have no meaning to a jpg file. And Windows can filter them out so will I.

Answer 1

如果在Vista或更高版本上运行，你可以使用'SHOpenWithDialog'http: //msdn.microsoft.com/en-us/library/bb762234 (v=vs.85) .aspx - 这很简单...... Jens

Answer 2

我认为您可以使用本文来验证并找出哪些适用于您的应用程序并且有效