XPath根据SQL Server xml中的属性“B”获取属性“A”的值

Question

I have this XML in SQL Server

<data>
<add key="images" value="image/path/img.gif" />
<data>

I want to select the value attribute of every "add" node with key = "images"

What i have now is:

SELECT ID, Data from Items 
where Data.value('(//data/add[@key="images"]/@value)[1]', 'nvarchar') Like '%img%'

Any suggestions?

Answer 1

What you have works fine if you just specify a size for your nvarchar retrieved from the XML.

SELECT ID, Data
from Items 
where Data.value('(//data/add[@key="images"]/@value)[1]', 'nvarchar(100)') Like '%img%'

Here I have specified 100 you may set it to something more appropriate for your situation. Without the size the column will have size 1 .

Answer 2

Use this XPath expression :

(//data
    /add
      [@key="images"]
         /@value
            [contains(.,"img")]
 )
 [1]