Linux-根据条件分割CSV

Question

I have a large CSV file with the following records:

60,1572236,3,58394247,\N,\N,\N,1925720,\N,2011-11-25 12:55:53,2011-11-25 12:55:53
61,2875109,4,58394209,1234,\N,4025175,\N,\N,2011-11-25 12:55:53,2011-11-25 12:55:53
62,2875109,4,58394209,\N,\N,\N,9860904,\N,2011-11-25 12:55:53,2011-11-25 12:55:53
63,2875109,5,58394209,8756,\N,\N,8615157,\N,2011-11-25 12:55:53,2011-11-25 12:55:53
64,2686696,3,58394211,\N,\N,59512,\N,\N,2011-11-25 12:55:53,2011-11-25 12:55:53
65,2686696,3,58394211,\N,\N,4025893,\N,\N,2011-11-25 12:55:53,2011-11-25 12:55:53

I want to split the file into 2 file, the condition for the split will be the value in the 5th column, one file will get the rows with no value in that column (\\N) and columns with value in that column will go to another file.

in the example above: rows 2,4 will go to one file and the rest of the rows will go to another file.

any ideas how to do this in linux?

Answer 1

You can use awk :

$ awk -F, '$5=="\\N"{print >"file1.csv"; next}; {print >"file2.csv"}' data.csv

• file1.csv will contains \\N
• file2.csv will contains others