为此获得boost :: shared_ptr

Question

I am making extensive use of boost:shared_ptr in my code. In fact, most of the objects that are allocated on the heap are held by a shared_ptr . Unfortunately this means that I can't pass this into any function that takes a shared_ptr . Consider this code:

void bar(boost::shared_ptr<Foo> pFoo)
{
    ...
}

void Foo::someFunction()
{
    bar(this);
}

There are two problems here. First, this won't compile because the T* constructor for shared_ptr is explicit. Second, if I force it to build with bar(boost::shared_ptr<Foo>(this)) I will have created a second shared pointer to my object that will eventually lead to a double-delete.

This brings me to my question: Is there any standard pattern for getting a copy of the existing shared pointer you know exists from inside a method on one of those objects? Is using intrusive reference counting my only option here?

Answer 1

You can derive from enable_shared_from_this and then you can use "shared_from_this()" instead of "this" to spawn a shared pointer to your own self object.

Example in the link:

#include <boost/enable_shared_from_this.hpp>

class Y: public boost::enable_shared_from_this<Y>
{
public:

    shared_ptr<Y> f()
    {
        return shared_from_this();
    }
}

int main()
{
    shared_ptr<Y> p(new Y);
    shared_ptr<Y> q = p->f();
    assert(p == q);
    assert(!(p < q || q < p)); // p and q must share ownership
}

It's a good idea when spawning threads from a member function to boost::bind to a shared_from_this() instead of this. It will ensure that the object is not released.

Answer 2

Just use a raw pointer for your function parameter instead of the shared_ptr. The purpose of a smart pointer is to control the lifetime of the object, but the object lifetime is already guaranteed by C++ scoping rules: it will exist for at least as long as the end of your function. That is, the calling code can't possibly delete the object before your function returns; thus the safety of a "dumb" pointer is guaranteed, as long as you don't try to delete the object inside your function.

The only time you need to pass a shared_ptr into a function is when you want to pass ownership of the object to the function, or want the function to make a copy of the pointer.

Answer 3

boost有这个用例的解决方案，请检查enable_shared_from_this

Answer 4

Are you really making more shared copies of pFoo inside bar? If you aren't doing anything crazy inside, just do this:

void bar(Foo &foo)
{
    // ...
}

Answer 5

With C++11 shared_ptr and enable_shared_from_this is now in the standard library. The latter is, as the name suggests, for this case exactly.

http://en.cppreference.com/w/cpp/memory/shared_ptr

http://en.cppreference.com/w/cpp/memory/enable_shared_from_this

Example bases on that in the links above:

struct Good: std::enable_shared_from_this<Good>{
    std::shared_ptr<Good> getptr() {
        return shared_from_this();
    }
};

use:

std::shared_ptr<Good> gp1(new Good);
std::shared_ptr<Good> gp2 = gp1->getptr();
std::cout << "gp2.use_count() = " << gp2.use_count() << '\n';

Answer 6

The function accepting a pointer wants to do one of two behaviors:

• Own the object being passed in, and delete it when it goes out of scope. In this case, you can just accept X* and immediately wrap a scoped_ptr around that object (in the function body). This will work to accept "this" or, in general, any heap-allocated object.
• Share a pointer (don't own it) to the object being passed in. In this case you do not want to use a scoped_ptr at all, since you don't want to delete the object at the end of your function. In this case, what you theoretically want is a shared_ptr (I've seen it called a linked_ptr elsewhere). The boost library has a version of shared_ptr , and this is also recommended in Scott Meyers' Effective C++ book (item 18 in the 3rd edition).

Edit: Oops I slightly misread the question, and I now see this answer is not exactly addressing the question. I'll leave it up anyway, in case this might be helpful for anyone working on similar code.