[英]error: void value not ignored as it ought to be
I am trying to get function symbol from a dynamic library and then I need to replace my function with the library funciton using the new function pointer.The code is to be written in c++ file. 我试图从动态库中获取函数符号,然后需要使用新的函数指针将函数替换为函数库。代码将用c ++文件编写。
I used following steps, 我使用了以下步骤,
{
void *temp = dlsym(<FLAGS>,<FUNC_NAME>);
*reinterpret_cast<void**>(&real_mal) = temp;
void *p = NULL;
p = real_mal(size);
return p;
}
But at compile time I am getting this "error: void value not ignored as it ought to be " error 但是在编译时,我遇到了这个“错误:void值不应该被忽略,因为它应该是”错误
How can I resolve above situation ? 如何解决以上情况?
Thanks 谢谢
Joachim's comment is right. 约阿希姆的评论是正确的。 The first problem is actually your cast.
第一个问题实际上是您的演员表。 The proper cast is
real_mal = reinterpret_cast<void*(size_t)>(dlsym(<FLAGS>,<FUNC_NAME>));
正确的转换为
real_mal = reinterpret_cast<void*(size_t)>(dlsym(<FLAGS>,<FUNC_NAME>));
. 。 Your current cast hides the incorrect declaration of
real_mal
. 您当前的演员表隐藏了
real_mal
的错误声明。
Once you've fixed that, you can just write return real_mal(size);
解决此问题后,您只需编写
return real_mal(size);
. 。
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