[英]Setting a variable inside a function in JS
var last = 0;
function grabProducts(searchstring) {
var last = 0;
$.post('ajax/products', {
method: 'search',
string: searchstring,
category: $('#search_category').val(),
sort: $('.sort').val()
}, function (data) {
data = $.parseJSON(data);
$.each(data, function (index, b) {
last = "dada";
});
});
}
alert(last);
Gives me alert with "0"
. 使用"0"
给我警报。 How can i make it set the variable to "dada"
? 我如何才能将变量设置为"dada"
?
You can't make a setup like that work because $.post()
is asynchronous . 您无法进行这样的设置,因为$.post()
是异步的 。 You'll have to put the "alert" in the callback function you pass to $.post()
. 您必须将“警报”放入传递给$.post()
的回调函数中。
var last=0;
function grabProducts(searchstring) {
var last=0;
$.post('ajax/products', { method: 'search', string: searchstring, category: $('#search_category').val(), sort: $('.sort').val() }, function(data) {
data = $.parseJSON(data);
$.each(data, function(index, b) {
last = "dada";
});
alert(last);
});
}
The whole point of the callback, in fact, is to provide you with a way to have code run when the HTTP request is complete. 实际上,回调的全部目的是为您提供一种在HTTP请求完成后运行代码的方式。
When you POST
something, It needs time for server to respond. 当你POST
的东西,它需要时间,服务器响应。 Do this: 做这个:
var last=0;
function grabProducts(searchstring) {
var last=0;
$.post('ajax/products', { method: 'search', string: searchstring, category: $('#search_category').val(), sort: $('.sort').val() }, function(data) {
data = $.parseJSON(data);
$.each(data, function(index, b) {
last = "dada";
});
alert(last);
});
}
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