getMinutes() 0-9 - 如何显示两位数？

Question

var date = "2012-01-18T16:03";
var date = new Date(date);

console.log(date.getMinutes());
console.log(date.getMinutes().length)

This returns 3.

1. How do I make it return '03'?
2. Why does .length return undefinded?

I tried this, but it did not work:

If strlen == 1 then num = ('0' + num);

Answer 1

var date = new Date("2012-01-18T16:03");

console.log( (date.getMinutes()<10?'0':'') + date.getMinutes() );

Answer 2

Yikes these answers aren't great, even the top post upticked. Here y'go, cross-browser and cleaner int/string conversion. Plus my advice is don't use a variable name 'date' with code like date = Date(...) where you're relying heavily on language case sensitivity (it works, but risky when you're working with server/browser code in different languages with different rules). So assuming the javascript Date in a var current_date :

mins = ('0'+current_date.getMinutes()).slice(-2);

The technique is take the rightmost 2 characters (slice(-2)) of "0" prepended onto the string value of getMinutes() . So:

"0"+"12" -> "012".slice(-2) -> "12"

and

"0"+"1" -> "01".slice(-2) -> "01"

Answer 3

Another short way is to fill the minutes with a leading zero using:

String(date.getMinutes()).padStart(2, "0");

Meaning: Make the string two chars long, if a char is missing then set 0 at this position.

See docs at str.padStart(targetLength, padString)

Answer 4

Elegant ES6 function to format a date into hh:mm:ss :

const leadingZero = (num) => `0${num}`.slice(-2);

const formatTime = (date) =>
  [date.getHours(), date.getMinutes(), date.getSeconds()]
  .map(leadingZero)
  .join(':');

Answer 5

I would like to provide a more neat solution to the problem if I may.The accepted answer is very good. But I would have done it like this.

Date.prototype.getFullMinutes = function () {
   if (this.getMinutes() < 10) {
       return '0' + this.getMinutes();
   }
   return this.getMinutes();
};

Now if you want to use this.

console.log(date.getFullMinutes());

Answer 6

I suggest:

var minutes = data.getMinutes();
minutes = minutes > 9 ? minutes : '0' + minutes;

it is one function call fewer. It is always good to think about performance. It is short as well;

Answer 7

使用 ECMAScript 国际化 API， 更多信息：

const twoDigitMinutes = date.toLocaleString('en-us', { minute: '2-digit' });

Answer 8

Another option:

var dateTime = new Date();
var minutesTwoDigitsWithLeadingZero = ("0" + dateTime.getMinutes()).substr(-2);

Answer 9

你应该检查它是否小于 10...不是在寻找它的长度，因为这是一个数字而不是一个字符串

Answer 10

I dont see any ES6 answers on here so I will add one using StandardJS formatting

// ES6 String formatting example
const time = new Date()
const tempMinutes = new Date.getMinutes()
const minutes = (tempMinutes < 10) ? `0${tempMinutes}` : tempMinutes

Answer 11

.length is undefined because getMinutes is returning a number, not a string. numbers don't have a length property. You could do

var m = "" + date.getMinutes();

to make it a string, then check the length (you would want to check for length === 1 , not 0).

Answer 12

Numbers don't have a length, but you can easily convert the number to a string, check the length and then prepend the 0 if it's necessary:

var strMonth = '' + date.getMinutes();
if (strMonth.length == 1) {
  strMonth = '0' + strMonth;
}

Answer 13

I assume you would need the value as string. You could use the code below. It will always return give you the two digit minutes as string.

var date = new Date(date);
var min = date.getMinutes();

if (min < 10) {
min = '0' + min;
} else {
min = min + '';
}
console.log(min);

Hope this helps.

Answer 14

I usually use this piece of code :

var start = new Date(timestamp),
    startMinutes = start.getMinutes() < 10 ? '0' + start.getMinutes() : start.getMinutes();

It is quite similar to the @ogur accepted answer but does not concatenate an empty string in the case that 0 is not needed. Not sure it is better. Just an other way to do it !

Answer 15

how about this? it works for me! :)

var d = new Date();
var minutes = d.getMinutes().toString().replace(/^(\d)$/, '0$1');

Answer 16

var d = new Date(date);
var dd = d.getDate();
var MM = d.getMonth();
var mm = d.getMinutes();
var HH = d.getHours();

// Hour
var result = ("0" + HH).slice(-2);

// Minutes
var result = ("0" + mm).slice(-2);

// Month
var result = ("0" + MM).slice(-2);

Answer 17

$(".min").append( (date.getMinutes()<10?'0':'') + date.getMinutes() );

new to JS so this was very helpful the most ppl looking at this prob new too so this is how i got it to show in the div called "class="min"

hope it helps someone

Answer 18

Another option to get two digit minutes or hours.

var date = new Date("2012-01-18T16:03");

var minutes = date.toTimeString().slice(3, 5); 
var hours   = date.toTimeString().slice(0, 2); 

Answer 19

you can use moment js :

moment(date).format('mm')

example : moment('2019-10-29T21:08').format('mm') ==> 08

hope it helps someone

Answer 20

对于两位数分钟使用： new Date().toLocaleFormat("%M")

Answer 21

If you're using AngularJS in your project, just inject $filter and use it like here:

$filter('date')(value, 'HH:mm')

You can also format the output in the template, more on filters here .