Ruby 1.9正则表达式对于无上下文语法同样强大吗？

Question

I have this regular expression:

regex = %r{\A(?<foo> a\g<foo>a | b\g<foo>b | c)\Z}x

When I test it against several strings, it appears to be as powerful as a context free grammar because it handles the recursion properly.

regex.match("aaacaaa")
# => #<MatchData "aaacaaa" foo:"aaacaaa">
regex.match("aacaa")
# => #<MatchData "aacaa" foo:"aacaa">
regex.match("aabcbaa")
# => #<MatchData "aabcbaa" foo:"aabcbaa">
regex.match("aaacaa")
# => nil

" Fun with Ruby 1.9 Regular Expressions " has an example where he actually arranges all the parts of a regex so that it looks like a context-free grammar as follows:

sentence = %r{ 
    (?<subject>   cat   | dog   | gerbil    ){0} 
    (?<verb>      eats  | drinks| generates ){0} 
    (?<object>    water | bones | PDFs      ){0} 
    (?<adjective> big   | small | smelly    ){0} 

    (?<opt_adj>   (\g<adjective>\s)?     ){0} 

    The\s\g<opt_adj>\g<subject>\s\g<verb>\s\g<opt_adj>\g<object> 
}x

Between his technique for rearranging the parts of the regex, and my example of recursive named capturing groups, does this mean Ruby 1.9 regular expressions have the power equivalent to a context-free grammar?

Answer 1

This is one of the awesome things about the Oniguruma regexp engine used in Ruby 1.9 – it has the power of a parser, and is not restricted to recognizing regular languages. It has positive and negative lookahead/lookbehind, which even can be used to recognize some languages which are not context-free! Take the following as an example:

regexp = /\A(?<AB>a\g<AB>b|){0}(?=\g<AB>c)a*(?<BC>b\g<BC>c|){1}\Z/

This regexp recognizes strings like “abc”, “aabbcc”, “aaabbbccc”, and so on – the number of “a”, “b”, and “c” must be equal, or it will not match.

(One limitation: you can't use named groups in the lookahead and lookbehind.)

Although I haven't peeked under the hood, Oniguruma seems to deal with named groups by simple recursive descent, backing up when something doesn't match. I've observed that it can't deal with left recursion. For example:

irb(main):013:0> regexp = /(?<A>\g<A>a|)/
SyntaxError: (irb):13: never ending recursion: /(?<A>\g<A>a|)/
    from C:/Ruby192/bin/irb:12:in `<main>'

I don't remember my parsing theory very clearly, but I think that a non-deterministic top-down parser like this should be able to parse any context-free language. (“language”, not “grammar”; if your grammar has left recursion, you will have to convert it to right recursion.) If that is incorrect, please edit this post.