[英]How to dump whole MySQL contents from PHP?
Is there a clean way (no hardcoding) in which I can dump all the contents of a database directly to HTML using PHP? 有没有一种干净的方法(无需硬编码),可以使用PHP将数据库的所有内容直接转储为HTML?
I don't want to run queries for every table and step through the results, outputting them. 我不想为每个表运行查询并单步执行结果,将其输出。 I need this for testing purposes, so the tables aren't that big.
我出于测试目的需要此表,因此表并不大。
Any hints? 有什么提示吗?
I want this done directly in my php file, where the rest of the test takes place, so that I may compare with the sample. 我希望直接在我的php文件中完成此操作,其余的测试将在该文件中进行,以便与示例进行比较。 I need to do this automatically, so can't really use tools like PHPMyAdmin.
我需要自动执行此操作,因此不能真正使用PHPMyAdmin之类的工具。
Something like this ought to work: 这样的事情应该起作用:
<?php
function dump_mysql_results($mysql_table){
$query = mysql_query("SELECT * FROM `$table` WHERE 1",[your connection]) or die(mysql_error());
if (!mysql_num_rows($query)){die("No rows in $table");}
while($r=mysql_fetch_array($query)){
if (!isset($html)){
$keys = array_keys($r);
$html = "<tr>";
foreach($keys as $key){
$html .= "<th>$key</th>";
}
$html .= "</tr>";
}
$html .= "<tr>";
foreach($r as $value){
$html .= "<td>$value</td>";
}
$html .= "</tr>";
}
return "<table>".$html."</table>";
}
//ADDING a loop to dump the whole db: //添加循环以转储整个数据库:
$tables = mysql_list_tables ( 'database name',$link_identifier) or die(mysql_error());
while($r=mysql_fetch_array($tables)){
echo dump_mysql_results($r[0]);
}
?>
Use SHOW TABLES to get the list of tables, then iterate through them normally to select all the rows and display in HTML. 使用SHOW TABLES获取表列表,然后正常地遍历它们以选择所有行并以HTML显示。
See http://dev.mysql.com/doc/refman/5.5/en/show-tables.html 见http://dev.mysql.com/doc/refman/5.5/en/show-tables.html
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