[英]grep in bash script not working as expected
If I run 如果我跑步
grep -i "echo" *
I get the results I want, but if I try the following simple bash script 我得到了想要的结果,但是如果尝试以下简单的bash脚本
#search.sh
grep -i "$1" *
echo "####--DONE--####"
and I run it with sh -x search.sh "echo"
I get the following error output: 然后用sh -x search.sh "echo"
运行它,得到以下错误输出:
' grep -i echo '*
: No such file or directory
' echo '####--DONE--####
####--DONE--####
How come? 怎么会? I'm on CentOS 我在使用CentOS
Add the sha-bang line at the top of your script 在脚本顶部添加“ shabang”行
#!/bin/bash
and after making it executable, run the script using 并使其可执行后,使用
./search.sh "echo"
The "sh -x" should print the files that '*' matches. “ sh -x”应打印与“ *”匹配的文件。 It looks like it's not matching any files. 似乎与任何文件都不匹配。 Are you maybe running it in a directory with no readable files? 您是否可能在没有可读文件的目录中运行它?
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