[英]Convert this SQL Server query to Oracle
I have the following in a SQL Server query which I have to convert to Oracle sp 我在SQL Server查询中有以下内容,必须将其转换为Oracle sp
DATEADD(dd, 0, DATEDIFF(dd, 0, DATEADD(ss, -L_LAST_TIME, TR.TR_DATETIME))) AS TRDATE,
Essentially you subtract L_LAST_TIME
seconds from TR_DATETIME
and then truncate the time part and keep only the date part. 基本上你减去
L_LAST_TIME
从秒TR_DATETIME
然后再截断时间部分,只保留日期部分。
You can divide intervals: 您可以划分间隔:
select trunc(TR.TR_DATETIME - interval L_LAST_TIME SECOND) AS TRDATE
or 要么
select trunc(TR.TR_DATETIME - NUMTODSINTERVAL(L_LAST_TIME, 'SECOND')) AS TRDATE
We can do arithmetic with dates in Oracle. 我们可以在Oracle中对日期进行算术运算。
select trunc(tr.tr_time - (l_last_time/86400)) as trdate
from tr
/
Dividing l_last_time
by 86400 turns a number of seconds into a fraction of day. 将
l_last_time
除以86400,可以将几秒钟变成一天的一小部分。 Subtracing it from the tr_time
column gives you a new, earlier date. 从
tr_time
列中对其进行tr_time
为您提供一个新的较早的日期。 Truncating a date removes the time component. 截断日期会删除时间部分。
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