[英]Array values to check another array values in PHP?
I have an array $minus
我有一个数组
$minus
array(3) { [0]=> string(6) "people"
[1]=> string(7) "friends"
[2]=> string(8) "siblings"
}
And I have an array $user
我有一个数组
$user
array(3) { ["people"]=> string(3) "100"
["friends"]=> string(2) "10"
["siblings"]=> string(2) "57"
}
I can get the values of $user
by using the values of $minus
like, 我可以通过使用
$minus
的值来获得$user
的值,
echo $user[$minus[0]] . ', ' . $user[$minus[1]] . ', ' . $user[$minus[2]];
// Would echo: 100, 10, 57
But how can I get the values of $user
by using the values of $minus
into a new array, the new array should be like, 但是如何通过将
$minus
的值使用到新数组中来获得$user
的值,新数组应该像这样,
array(3) { [0]=> string(3) "100"
[1]=> string(2) "10"
[2]=> string(2) "57"
}
I have tried using foreach
loops but can never get it right? 我已经尝试过使用
foreach
循环,但是永远无法正确执行?
foreach($minus as $key=>$value) {
$new_array[$key] = $user[$value];
}
仅使用array_map
,PHP> = 5.3
$new_array = array_map(function($item) use ($user) {return $user[$item];}, $minus);
$new_array= array();
foreach ($minus as $key => $value){
$new_array[$key] = $user[$value];
}
print_r($new_array);
$new_array = array($user[$minus[0]], $user[$minus[1]], $user[$minus[2]]);
$minus = array(0 => "people",
1 => "friends",
2 => "siblings"
);
$user = array("people" => "100",
"friends" => "10",
"siblings" => "57"
);
$newArray = $minus;
array_walk($newArray,function(&$item, $key, $prefix) { $item = $prefix[$item]; },$user);
var_dump($newArray);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.