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JAX-RS：如何返回响应并继续在后端处理请求

[英]JAX-RS : How to return a response and continue processing the request in the back end

原文 2012-01-26 00:30:42 0 1 java/ web-services/ jax-rs

we are using Jax-rs (out of box on WebSphere 7 : no other frameworks like CXF or Restfull or Spring) question: Client makes a http call, the server takes 3 to 5 minutes to process the request. 我们正在使用Jax-rs（在WebSphere 7上开箱即用：没有其他框架，如CXF或Restfull或Spring）问题：客户端进行http调用，服务器需要3到5分钟来处理请求。 however I do not want to hold the client, I want to return http OK response and then spin off processing call. 但是我不想持有客户端，我想返回http OK响应，然后关闭处理调用。

How to do this in JAX-RS, I am hoping there is some kind of annotations. 如何在JAX-RS中执行此操作，我希望有某种注释。 I really do not want to get into spinning off a thread and managing it (no complex solutions with threading). 我真的不想进入一个线程并管理它（没有复杂的线程解决方案）。

Thanks for your help 谢谢你的帮助

1 个解决方案

I don't see any other solution then starting another thread (thread management is easier then it was before java.util.concurrent, so give it a chance). 我没有看到任何其他解决方案，然后启动另一个线程（线程管理比java.util.concurrent之前更容易，所以给它一个机会）。

The other solution is to make AJAX calls to the REST service. 另一种解决方案是对REST服务进行AJAX调用。 AJAX + promises implementation (jQuery promises or more feature rich Q promises library) would make waiting for the service response very easy. AJAX +承诺实现（jQuery承诺或更多功能丰富的Q promises库）将使等待服务响应变得非常容易。