最小长度正则表达式

Question

I'm trying to write a regular expression that will validate that user input is greater than X number of non-whitespace characters. I'm basically trying to filter out begining and ending whitespace while still ensuring that the input is greater than X characters; the characters can be anything, just not whitespace (space, tab, return, newline). This the regex I've been using, but it doesn't work:

\s.{10}.*\s

I'm using C# 4.0 (Asp.net Regular Expression Validator) btw if that matters.

Answer 1

It may be easier to not use regex at all:

input.Where(c => !char.IsWhiteSpace(c)).Count() > 10

If whitespace shouldn't count in the middle, then this will work:

(\s*(\S)\s*){10,}

If you don't care about whitespace in between non-whitespace characters, the other answers have that scenario covered.

Answer 2

此正则表达式在第一个和最后一个非空白字符之间查找八个或更多字符，忽略前导和尾随空格：

\s*\S.{8,}\S\s*

Answer 3

如果您尝试检查（就像我的情况下包含8位数字的电话号码），您需要参考您需要的号码。

(\s*(\S)\s*){7,}