[英]php: how to regex replace the following strings?
would like to replace all occurence of, double quote included 想替换所有出现的情况,包括双引号
"http://somebunchofchar"
to 至
"link"
I came up with preg_replace("/\\"http:\\/\\/.\\"/i", "\\"link\\"", $string);
我想出了preg_replace("/\\"http:\\/\\/.\\"/i", "\\"link\\"", $string);
只需在点后添加星号和问号
preg_replace("/\\"http:\\/\\/.*?\\"/i", "\\"link\\"", $string);
$string = preg_replace('#"http://.+"#', '"link"', $string);
您可以使用:
preg_replace('~"http://[^"]*"~i', '"link"', $string);
Just look here: http://regexlib.com/DisplayPatterns.aspx?cattabindex=1&categoryId=2&AspxAutoDetectCookieSupport=1 how to match an URL with the correct pattern; 只需看这里: http : //regexlib.com/DisplayPatterns.aspx ?cattabindex=1&categoryId=2& AspxAutoDetectCookieSupport=1如何将URL与正确的模式进行匹配; than use preg_replace with the particular regexp pattern ;-) (you can add those quotes at the start and end to the pattern yourself quite easily) :-) 而不是将preg_replace与特定的regexp模式一起使用;-)(您可以很容易地在模式的开始和结束处添加这些引号):-)
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