Spring MVC：动态404页面

Question

<error-page>
    <error-code>404</error-code>
    <location>/404.html</location>
</error-page>

This is my current configuration for 404 errors.

What I want: When a person types www.host.com/word . I want the string "word" as input for my search url (which is www.host.com/search.do?keyword).

Does anyone know how to do this?

Answer 1

Map / to your DispatcherServlet (see section 16.2 of the Spring reference documentation) and set up a URI template as shown in section 16.3.2.1 . For example, you could set up a request mapping like so:

@RequestMapping(value="/{keyword}", method=RequestMethod.GET)
public ModelAndView doSearch(@PathVariable("keyword") String keyword)
{
  // forward to your search page
}