Firebug为什么说$ .cookie（）不是函数？

Question

I am trying to set a cookie with jQuery 1.7.1:

var global_namesArray = ["Alex", "Bob", "Carmen"];
$.cookie("namesArray", global_namesArray);

I retrieve this cookie like this:

if ($.cookie("namesArray") != null)
    global_namesArray = $.cookie("namesArray");

However, the page's javascript does not load. When I use Firebug to analyze my page, the console reads that $.cookie() is not a function. The error occurs during cookie retrieval I believe. I am sure that I have linked jQuery.

Am I using the jQuery $.cookie() function correctly?

Answer 1

.cookie is not a native function for jQuery. Do you have the cookie plugin installed?

Edit: I just tested, and I get this error if I include jQuery but not the cookie plugin:

"$.cookie is not a function".

You probably just need to add the cookie plugin.

Answer 2

确保jquery.cookie.js之后包括jquery.js ，那你是不是其中jquery.js不止一次。