简体   繁体   English

鉴于Object是一个任何类型的数组,你如何测试它在Java中是空的?

[英]Given that an Object is an Array of any type how do you test that it is empty in Java?

Please help me complete my isEmpty method: 请帮我完成我的isEmpty方法:

public static boolean isEmpty(Object test){
    if (test==null){
        return true;
    }
    if (test.getClass().isArray()){
        //???
    }
    if (test instanceof String){
        String s=(String)test;
        return s=="";
    }
    if (test instanceof Collection){
        Collection c=(Collection)test;
        return c.size()==0;
    }
    return false;
}

What code would I put int to establish that if I am dealing with an array it will return true if it's length is zero? 我将int设置为什么代码来确定如果我正在处理一个数组,如果它的长度为零,它将返回true? I want it to work no matter the type whether it is int[], Object[]. 无论类型是int [],Object [],我希望它能工作。 (Just so you know, I can tell you that if you put an int[] into an Object[] variable, it will throw an exception.) (大家都知道,我可以告诉你,如果你把一个int []放到一个Object []变量中,它会抛出异常。)

You can use the helper method getLength(Object) from java.reflect.Array : 您可以使用java.reflect.Array的helper方法getLength(Object)

public static boolean isEmpty(Object test){
    if (test==null){
        return true;
    }
    if (test.getClass().isArray()){
        return 0 == Array.getLength(test);
    }
    if (test instanceof String){
        String s=(String)test;
        return s.isEmpty(); // Change this!!
    }
    if (test instanceof Collection){
        Collection c=(Collection)test;
        return c.isEmpty();
    }
    return false;
}

Note that you can't use 请注意,您无法使用

boolean empty = (someString == "");

because that is not safe. 因为那不安全 For comparing strings, use String.equals(String) , or in this case, just check if the length is zero. 要比较字符串,请使用String.equals(String) ,或者在这种情况下,只检查长度是否为零。

You can use java.lang.reflect.Array#getLength . 您可以使用java.lang.reflect.Array#getLength

Also note that your test for String won't work as you expect. 另请注意,您对String的测试将无法按预期工作。

构建一些空检查的第三个选项是Apache的ArrayUtils

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM