没有参数的 Nginx request_uri

Question

How do I get the value of request_uri without the args appended on the end. I know there is a uri variable but I need the original value as the Nginx documentation states:

request_uri

This variable is equal to the original request URI as received from the client including the args. It cannot be modified. Look at $uri for the post-rewrite/altered URI. Does not include host name. Example: "/foo/bar.php?arg=baz"

Answer 1

I use this map, which works without lua:

map $request_uri $request_uri_path {
  "~^(?P<path>[^?]*)(\?.*)?$"  $path;
}

Answer 2

You're looking for $uri. It does not have $args. In fact, $request_uri is almost equivalent to $uri$args.

If you really want exactly $request_uri with the args stripped, you can do this.

local uri = string.gsub(ngx.var.request_uri, "?.*", "")

You will need to have lua available but that will do exactly what you're asking.

Answer 3

The accepted answer pointed me in the right direction, but I had to figure out where to add that directive, After some time investigating I found set_by_lua_block

set_by_lua_block $request_uri_path {
    return string.gsub(ngx.var.request_uri, "?.*", "")
}

I hope it saves some time to those who comes here.

Answer 4

Ryan Olson's answer is really good but map cannot be used everywhere.

If you need to get that information at a block level that does not accept the use of map , it can be done in a if statement. But remember that if is evil .

set $new_uri "";
if ($request_uri ~ "^([^?]*)(\?.*)?$") {
    set $new_uri $1;
}

This code works out of the box (it does not use Lua or anything else).