[英]jetty 8 - websockets : how do I get the client IP address?
Simple task. 简单的任务。 I'm using the websockets server implementation by jetty, and I have to get the client IP address, but I don't know how.
我正在通过码头使用websockets服务器实现,我必须获取客户端IP地址,但是我不知道如何。
I think it is same as it always was, grab IP from HTTPServletRequest#getRemoteAddr()
like this: 我认为它与往常一样,从
HTTPServletRequest#getRemoteAddr()
获取IP,如下所示:
public class WSServlet extends WebSocketServlet {
...
...
@Override
public WebSocket doWebSocketConnect(HttpServletRequest req, String str) {
System.out.println("IP: "+ req.getRemoteAddr());
...
}
}
如果您使用的是org.eclipse.jetty.websocket.api.Session
我将寻求:
session.getRemoteAddress().getAddress().getHostAddress();
If you need it for authentification purposes, you can get it like this: 如果出于身份验证目的需要它,则可以这样获得:
This is just an example: 这只是一个例子:
@Override
public boolean canPublish(BayeuxServer server, ServerSession client,
ServerChannel channel, ServerMessage messsage) {
//
BayeuxContext context=server.getContext();
System.out.println(context.getRemoteAddress());
return true;
}
Please keep in mind that getRemoteAddress
returns an InetSocketAddress
string. 请记住,
getRemoteAddress
返回一个InetSocketAddress
字符串。 So you also have the port, which looks something like this: 因此,您还有端口,看起来像这样:
/79.111.111.22:49372
Without WebServletSocket: 如果没有WebServletSocket:
public static String getClientIp(Session session) {
String ip = session.getUserProperties().get("javax.websocket.endpoint.remoteAddress").toString();
int i1 = ip.indexOf("/");
int i2 = ip.indexOf(":");
return ip.substring(i1 + 1, i2);
}
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