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Question

when I'm running this script (from a .bat file):

set var1=true
if "%var1%"=="true" (
  set var2=myvalue
  echo %var2%
)

I always get:

ECHO is on.

Meaning the var2 variable was not really set. Can anyone please help me understand why?

Answer 1

var2 is set, but the expansion in the line echo %var2% occurs before the block is executed.
At this time var2 is empty.

Therefore the delayedExpansion syntax exists, it uses ! instead of % and it is evaluated at execution time, not parse time.

Please note that in order to use ! , the additional statement setlocal EnableDelayedExpansion is needed.

setlocal EnableDelayedExpansion
set var1=true
if "%var1%"=="true" (
  set var2=myvalue
  echo !var2!
)

Answer 2

I am a bit late to the party but another way to deal with this condition is to continue process outside if , like this

set var1=true
if "%var1%"=="true" (
    set var2=myvalue
)
echo %var2%

Or/and use goto syntax

set var1=true
if "%var1%"=="true" (
    set var2=myvalue
    goto line10
) else (
    goto line20
)
. . . . .
:line10
echo %var2%
. . . . . 
:line20

This way expansion occurs "in time" and you don't need setlocal EnableDelayedExpansion . Bottom line, if you rethink design of your script you can do it like that