[英]Getting multiple counts from two joined tables in MySQL
So I have two tables, categories and designs. 因此,我有两个表,类别和设计。 I want to construct a query that will fetch all categories, along with the count of any sub categories (categories.parent_id equal to the categories.id) AND the count of any designs (design.category_id equal to categories.id) 我想构造一个查询,该查询将获取所有类别以及所有子类别的计数(categories.parent_id等于category.id)和任何设计的计数(design.category_id等于category.id)
If I try to just get one of these counts, everything works fine, but when I try for both with the following code, the count for both is the same number (and not the correct number) for either. 如果我尝试仅获取这些计数之一,那么一切正常,但是当我使用以下代码尝试两者时,两者的计数都是相同的数字(而不是正确的数字)。
$this->db->select('categories.id AS id, categories.parent_id AS parent_id, categories.title AS title,
categories.description AS description, categories.img_path AS img_path, COUNT(designs.id) AS design_count,
COUNT(sub_categories.id) as sub_category_count');
$this->db->from('categories');
$this->db->join('designs', 'categories.id = designs.category_id', 'left');
$this->db->join('categories as sub_categories', 'categories.id = sub_categories.parent_id', 'left');
$this->db->group_by('categories.id');
Any help will be much appreciated, cheers! 任何帮助将不胜感激,加油!
Assuming that the root categories do not contain designs, here is the query that returns the necessary information: 假设根类别不包含设计,以下是返回必要信息的查询:
SELECT category.id, category.title, subcategory.id, designs.id
FROM categories category
LEFT JOIN categories subcategory ON category.id = subcategory.parent_id
LEFT JOIN designs ON subcategory.id = designs.category_id
WHERE category.parent_id IS NULL
Now all you need to do is to apply grouping: 现在,您需要做的就是应用分组:
SELECT category.id, category.title, COUNT(DISTINCT subcategory.id), COUNT(designs.id)
FROM categories category
LEFT JOIN categories subcategory ON category.id = subcategory.parent_id
LEFT JOIN designs ON subcategory.id = designs.category_id
WHERE category.parent_id IS NULL
GROUP BY category.id, category.title
The key here is the use of COUNT(DISTINCT ...)
. 这里的关键是使用COUNT(DISTINCT ...)
。
SELECT c.id,c.title,
IFNULL(sc.counted,0) AS subcategories,
IFNULL(d.counted,0) AS designs
FROM categories c
LEFT JOIN
( SELECT parent_id,COUNT(*) AS counted
FROM categories GROUP BY parent_id ) sc
ON c.id=sc.parent_id
LEFT JOIN
( SELECT category_id,COUNT(*) AS counted
FROM designs GROUP BY category_id ) d
ON c.id=d.category_id
WHERE c.parent_id IS NULL ;
should get you the desired numbers as raw SQL. 应该为您提供所需的数字作为原始SQL。
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