[英]MVC3 Binding model (some fields) to the view
Binding model to the view. 将模型绑定到视图。
my model Person has {Id,Title,Address...etc) 我的模特人有{Id,Title,Address ... etc)
In my controller I want to retrieve some fields eg: 在我的控制器中,我想检索一些字段,例如:
var model = from p in db.Person where p.jobtype == 1
select new Person { Title = p.Title, Address = p.Address};
return View(model);
also tried to to use anonymous type and it doesn't work: 也试图使用匿名类型,它不起作用:
var model = from p in db.Person where p.jobtype == 1
select new { p.Title, p.Address};
return View(model);
In my view: 在我看来:
@model IEnumerable<Demo.Models.Person>
@foreach (var item in Model) {
<div>@item.Title</div>} >FAILS
If I retrieve full object then it works, how do I retrieve some fields using anonymous type or\\and using my model.... plz provide the correct syntax. 如果我检索到完整的对象,那么它将起作用,如何使用匿名类型或\\和我的模型来检索某些字段。...plz提供正确的语法。 Thanks
谢谢
If your View is requiring the Model to be Enumerable
then it needs to be AsEnumerable
in your select statement. 如果你的观点是需要模型是
Enumerable
那么它需要AsEnumerable
在你的SELECT语句。
var model = (from p in db.Person
where p.jobtype == 1
select p).AsEnumerable();
return View(model);
and then 接着
@model IEnumerable<Demo.Models.Person>
@foreach (var item in Model.ToList()) {
<div>@item.Title</div>}
Alternatively, Since you just need a list at the end of the day, and you "should" be using a ViewModel, I suggest the following. 或者,由于您只需要一天结束时的列表,并且“应该”使用ViewModel,因此建议以下内容。
ViewModel 视图模型
public class PersonViewModel
{
public int Name { get; set; }
public string Title { get; set; }
}
Controller 控制者
var person = (from p in db.Person
where p.jobtype == 1
select p);
PersonViewModel model = Mapper.Map<Person, PersonViewModel>(person);
return View(model.ToList());
View 视图
@model List<Demo.ViewModels.PersonViewModel>
@foreach (var item in Model) {
<div>@item.Title</div>}
note: I used AutoMapper in the above example 注意:我在上面的示例中使用了AutoMapper
I don't have my IDE in front of me, so I'm not sure if this is perfect. 我没有我的IDE,所以我不确定这是否完美。
You can use .ToList() : 您可以使用.ToList():
List<person> model = (from p in db.Person
where p.jobtype == 1
select p).ToList();
return View(model);
In your view : 在您看来:
@model List<person>
@foreach (var item in Model) {
}
I would recommend that you call your data db.People
or something like that. 我建议您将数据
db.People
或类似的名称。
You should use p.ID == 3
instead of p.ID = 3
. 您应该使用
p.ID == 3
而不是p.ID = 3
。
If your intention is to only select one Person and display then use SingleOrDefault()
, First()
, FirstOrDefault()
to get only a single Person-entry. 如果您打算只选择一个Person并显示,则使用
SingleOrDefault()
, First()
, FirstOrDefault()
仅获得一个Person输入。
var model = (from p in db.Person where p.ID == 3
select p.Title).First();
Then in your model don't use IEnumerable, just use: 然后在您的模型中不要使用IEnumerable,只需使用:
@model Demo.Models.Person
<div>@item.Title</div>
EDIT: after you updated question to contain p.jobtype instead of p.ID to select multiple I would recommend using a specific ViewModel for the data you wish to select. 编辑:更新问题以包含p.jobtype而不是p.ID选择多个后,我建议对您要选择的数据使用特定的ViewModel。 If all you want is Title then you could use
如果您只想要标题,那么您可以使用
@model IEnumerable<string>
@foreach (var title in Model) {
<div>@title</div>}
But I would recommend using a specific ViewModel with only the fields you require, for example: 但是我建议仅将特定的ViewModel与所需的字段一起使用,例如:
public class PersonViewModel
{
public int Name { get; set; }
public string Title { get; set; }
}
and then select new PersonViewModel {Name = p.Name, Title = p.Title }
and of course use that model in the view: @model IEnumerable<PersonViewModel>
. 然后
select new PersonViewModel {Name = p.Name, Title = p.Title }
,当然@model IEnumerable<PersonViewModel>
在视图中使用该模型: @model IEnumerable<PersonViewModel>
。
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