[英]Sql Server 2008 Shredding XML
Hi I have some XML like this... 嗨我有这样的XML ...
<Questions>
<Question1>A</Question1>
<Question2>B</Question2>
<Question3>C</Question3>
</Questions>
I would like to return A,B,C. 我想回A,B,C。 I have seen some similar questions but those had the same repeating node name.
我见过一些类似的问题,但那些具有相同的重复节点名称。 Unfortunately at this stage I cant change it.
不幸的是,在这个阶段我无法改变它。 I have played with the SQL Xpath syntax for AGES, with no luck.
我玩过AGES的SQL Xpath语法,没有运气。 I can get the whole Questions Node, but Ideally I would like the Actual Data.
我可以获得整个问题节点,但理想情况下我想要实际数据。 Multiple returned rows would also be OK.
多个返回的行也可以。
Any help would be greatly appreciated. 任何帮助将不胜感激。
Update - Kirill's answer is very close, except that I have more than 1 record in the table and it is returning all records data within 1 row. 更新 - 基里尔的答案非常接近,除了我在表中有超过1条记录并且它返回1行内的所有记录数据。 If I could achieve a row/xml file that would be perfect !!!
如果我能实现一个完美的row / xml文件! Either by outputing another field from that record eg rownum or outputting another piece of data from the file eg ProfileName..
通过从该记录输出另一个字段,例如rownum或从文件输出另一个数据,例如ProfileName ..
thanks, 谢谢,
Adrian ! 阿德里安!
declare @x xml = N'<Questions>
<Question1>A</Question1>
<Question2>B</Question2>
<Question3>C</Question3>
</Questions>
'
SELECT x.value('.','varchar(10)')
FROM @x.nodes('/Questions/*') x(x)
Output 产量
----------
A
B
C
Continuing on Martin's solution and with some inspiration from this : 继续对马丁的解决方案,并与一些灵感此 :
declare @x xml = N'<Questions>
<Question1>A</Question1>
<Question2>B</Question2>
<Question3>C</Question3>
</Questions>
'
DECLARE @Questions VARCHAR(MAX)
SELECT @Questions = COALESCE(@Questions + ', ', '') + Question
FROM (
SELECT x.value('.','varchar(10)') as Question
FROM @x.nodes('/Questions/*') x(x)
) as y
SELECT @Questions
Output: 输出:
A, B, C
Use: 采用:
declare @x xml ='
<Questions>
<Question1>A</Question1>
<Question2>B</Question2>
<Question3>C</Question3>
</Questions>'
select @x.value('(/*/Question1)[1]', 'nvarchar(max)')
, @x.value('(/*/Question2)[1]', 'nvarchar(max)')
, @x.value('(/*/Question3)[1]', 'nvarchar(max)')
Output: 输出:
---- ---- ----
A B C
select stuff(
(
select ',' + x.value('.', 'varchar(10)') [text()]
from @x.nodes('/*/*') x(x)
for xml path(''))
, 1, 1, '')
Output: 输出:
A,B,C
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