在java中反向使用Thread.join（）

Question

I know that I can use the following to have thread B waiting for thread A to finish before proceeding:

class A extends Thread{
    public void run(){
        ....
    }
}
class B extends Thread{
    private Thread someThread;
    B(Thread t){
        someThread=t;
    }
    public void run(){
        someThread.join();
        ...//then proceed
    }
}

But how can I do this in the run() of A to call B and then wait it finish before proceeding? That is, I want something like

class A extends Thread{
    private Thread someThread;
    B(Thread t){
        someThread=t;
    }
    public void run(){
        //*how to start B and wait it finish?
        ...//then proceed
    }
}
class B extends Thread{
    public void run(){
        ....
    }
}

Answer 1

Same deal:

class A extends Thread{
    private Thread someThread;
    A(Thread t){
        someThread=t;
    }
    public void run(){
        someThread.start();
        someThread.join();
        // proceed
    }
}
class B extends Thread{
    public void run(){
        ....
    }
}

Answer 2

If possible, a simpler solution would be to start B first, then b.join(); , and do the same for A in the client code:

b.start();
b.join();
a.start();
a.join();

There is no sense in starting a thread for it to just fire up and join on another tread before proceeding.

Answer 3

Find below example for how to reverse execute the thread.?

We can use join method for this case.

    package interview.thread;
     public class RevarseThreadExcute {
    public static void main(String[] args) throws InterruptedException {
   Thread t3 = new Thread(new Runnable() {
    @Override
            public void run() {

                for (int i = 0; i < 10; i++) {
                    System.out.println("Thread 3 =" + i);

                }
            }
        });
        Thread t2 = new Thread(new Runnable() {

            @Override
            public void run() {
               try {
                t3.join();
            } catch (InterruptedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
                for (int i = 0; i < 10; i++) {
                    System.out.println("Thread 2 =" + i);

                }
            }
        });

        Thread t1 = new Thread(new Runnable() {

            @Override
            public void run() {
                try {
                    t3.join();
                    t2.join();
                } catch (InterruptedException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
                for (int i = 0; i < 10; i++) {
                    System.out.println("Thread 1 =" + i);

                }
            }
        });

        t1.start();
        t2.start();
        t3.start();
    }


}

outpot:

Thread 3 =0
Thread 3 =1
Thread 3 =2
Thread 3 =3
Thread 3 =4
Thread 3 =5
Thread 3 =6
Thread 3 =7
Thread 3 =8
Thread 3 =9
Thread 2 =0
Thread 2 =1
Thread 2 =2
Thread 2 =3
Thread 2 =4
Thread 2 =5
Thread 2 =6
Thread 2 =7
Thread 2 =8
Thread 2 =9
Thread 1 =0
Thread 1 =1
Thread 1 =2
Thread 1 =3
Thread 1 =4
Thread 1 =5
Thread 1 =6
Thread 1 =7
Thread 1 =8
Thread 1 =9

Answer 4

class A extends Thread{

    private Thread someThread;

    B(Thread t){
        someThread=t;
    }
    public void run(){
        someThread.join()
        //do stuff
    }
}

class B extends Thread{

    public void run(){
        ....
    }
}

Answer 5

Thread b = new B();
b.start();
b.join();

But why would you want to? The idea of threads is to do things in parallel. Why would you start a thread and immediately wait for it to finish? Just execute the stuff from B in place in A.

Answer 6

You can use join() to wait for any thread.

final Thread a = Thread.currentThread();
new Thread(new Runnable() {
    public void run() {
        // do something
        a.join();
        // calling thread finished.
    }
 }).start();
 // do something.