提升线程代码〜uintmax_t（0）

Question

bool is_sentinel() const
{
    return milliseconds==~uintmax_t(0);
}

I have found this line of code in thread_data.hpp, I am wondering why is it ~uintmax_t(0) instead of -1 ?

EDIT:

if reason is to avoid compiler warnings, why don't use :

std::numeric_limits(decltype(milliseconds)>::max()

?

Answer 1

One reason for using uintmax_t in the first place is that we don't know what the largest type is. Is it unsigned long or unsigned long long ?

My guess is that using ~uintmax_t(0) to produce a large unsigned value simply produces the least number of warnings on the largest number of compilers.

It is common for compilers to warn if you mix signed and unsigned values, or that using a minus on an unsigned value ( -1ull ) surprisingly(?) gives an unsigned result.

Answer 2

~uintmax_t(0)是产生不产生编译器警告的uintmax_t类型的全值的最简单方法。

Answer 3

由于milliseconds是无符号的，因此将其与-1比较没有任何意义。