从输出生成xml文件

Question

So far i wrote a code to download a file from ftp server then using 3rd party dll (media info) to get the metadata details about the file. Until this am good,now am trying to generate the xml file based on my output ,i seen great examples here How can I build XML in C#? to generate xml but my scenario is little bit different,thats why i created this thread.

below is the code to get the properties value of jpg file

 static void Main(string[] args)
 {
     try
     {

         string file = "test.jpg";
         FtpWebRequest reqFTP;
         string ftpserverIp = "1.0.0.1";
         string fileName = @"c:\downloadDir\" + file;
         FileInfo downloadFile = new FileInfo(fileName);
         FileStream outputStream = new FileStream(fileName, FileMode.Append);
         reqFTP = (FtpWebRequest)FtpWebRequest.Create(new Uri("ftp://" + ftpserverIp + "/" + file));
         reqFTP.Method = WebRequestMethods.Ftp.DownloadFile;
         reqFTP.UseBinary = true;
         reqFTP.KeepAlive = false;
         reqFTP.Timeout = -1;
         reqFTP.UsePassive = true;
         reqFTP.Credentials = new NetworkCredential("sh", "SE");
         FtpWebResponse response = (FtpWebResponse)reqFTP.GetResponse();
         Stream ftpStream = response.GetResponseStream();
         long cl = response.ContentLength;
         // reqFTP.Method = WebRequestMethods.Ftp.ListDirectory;
         int bufferSize = 4096;
         int readCount;
         byte[] buffer = new byte[bufferSize];
         readCount = ftpStream.Read(buffer, 0, bufferSize);
         Console.WriteLine("Connected: Downloading File");
         while (readCount > 0)
         {
             outputStream.Write(buffer, 0, readCount);
             readCount = ftpStream.Read(buffer, 0, bufferSize);
             Console.WriteLine(readCount.ToString());
         }

         ftpStream.Close();
         outputStream.Close();
         response.Close();
         Console.WriteLine("Downloading Complete");
         var message = new StringBuilder();
         ConsoleApplication2.Program TechMeta = new ConsoleApplication2.Program();
         TechMeta.PutMessage(file, message);
         Console.WriteLine(message);
     }
     catch (Exception ex)
     {
         Console.Write(ex);
     }


 }

 private void PutMessage(string filename, StringBuilder message)
 {

     //Check the file is video or Image file here
     string extension =".jpg";

     bool b;
     if (b = filename.Contains(extension))
     {

         HowToUse_Dll.ImageInterrogator imageInterrogator = new HowToUse_Dll.ImageInterrogator();
         imageInterrogator.LoadFile(filename);
         message.AppendFormat(messageFormat, "Width", imageInterrogator.GetWidth(), Environment.NewLine);
         message.AppendFormat(messageFormat, "Height", imageInterrogator.GetHeight(), Environment.NewLine);
         message.AppendFormat(messageFormat, "FileSize", imageInterrogator.GetFileSize(), Environment.NewLine);
         message.AppendFormat(messageFormat, "FileFormat", imageInterrogator.GetFileFormat(), Environment.NewLine);
         message.AppendFormat(messageFormat, "Resolution", imageInterrogator.GetResolution(), Environment.NewLine);
     }
     else
     {

          HowToUse_Dll.VideoInterrogator videoInterrogator = new HowToUse_Dll.VideoInterrogator();
          videoInterrogator.LoadFile(filename);
          message.AppendFormat(messageFormat, "FileSize", videoInterrogator.GetFileSize(), Environment.NewLine);
          message.AppendFormat(messageFormat, "Duration", videoInterrogator.GetDuration(), Environment.NewLine);
          message.AppendFormat(messageFormat, "AspectRatio", videoInterrogator.GetAspectRatio(), Environment.NewLine);
          message.AppendFormat(messageFormat, "GetAspectRatio", videoInterrogator.GetAspectRatio(), Environment.NewLine);
          message.AppendFormat(messageFormat, "BitRate", videoInterrogator.GetBitRate(), Environment.NewLine);
          message.AppendFormat(messageFormat, "Format", videoInterrogator.GetFormat(), Environment.NewLine);
          message.AppendFormat(messageFormat, "VideoCoder", videoInterrogator.GetVideoCoder(), Environment.NewLine);
          message.AppendFormat(messageFormat, "Redirector", videoInterrogator.GetRedirector(), Environment.NewLine);
          message.AppendFormat(messageFormat, "TargetPlayback", videoInterrogator.GetTargetPlayback(), Environment.NewLine);
     }

 }

 public string messageFormat
 {
     get
     {
         return "{0}: {1}{2}";
     }
 }

base on the test.jpg file it ,TechMeta.PutMessage(file, message); Message value are

    {Width: 1024
     Height: 576
     FileSize: 84845
     FileFormat: JPEG
     Resolution: 8
     }

Now am trying to generate xml file based on the value like below,the more importantly am trying to append based on new file like below

<image Name="test.jpg">
<width>1024</width>
<height>576</height>
<file-Size>84845</file-Size>
<resolution>8</resolution>
<image Name="test1.jpg">
<width>1024</width>
<height>576</height>
<file-Size>84845</file-Size>
<resolution>8</resolution>

Any suggestion please

Answer 1

You might want to take a look into the class XmlWriter .

Edit: Wrong Link, fixed now.