表单提交前的jQuery模式对话框

Question

I have a form on a page, and I am trapping the click action on two submit buttons. There is another submit button that is not trapped (ie I dont need to show a modal for this button).

So, my obvious problem is that I need to block the submit action when the modal first opens, and I then need to force the submit when the user actually clicks the OK button in the modal. However, because each button has a specific name and value associated with it (which the back-end script needs to know), a $('#myform').submit() method will therefore not work.

function something(msg) {
    var $dialog = $('<div></div>').html(msg).dialog({
        autoOpen: false,
        title: 'Please confirm...',
        modal: true,
        buttons: {
            "OK": function () {
                $dialog.dialog('close');
                //submit needs to happen here
            },
            Cancel: function () {
                $(this).dialog("close");
            }
        }
    });
    $dialog.dialog('open');
    event.preventDefault();
    return false;
}

Answer 1

I would include a hidden field to take on the name and value of the submit button clicked:

<input type="hidden" name="subName" value="" />

$("#submit_button_one").function() {
    $("input[name='subName']").attr("name", $(this).attr("name")).val(($(this).val());
    something("message");
    return false;
});
$("#submit_button_two").function() {
    $("input[name='subName']").attr("name", $(this).attr("name")).val(($(this).val());
    something("message");
    return false;
});

function something(msg, act) {
    // ...
    //submit needs to happen here
    $('#myform').submit()
}