HTML5 Canvas中旋转矩形内的鼠标位置

Question

Rotation of rectangles within an html5 canvas is being stored in radians. In order to find whether subsequent mouse clicks are within any given rectangle, I am translating the mouse x and y to the origin of rotation for the rectangle, applying the reverse of the rotation to the mouse coordinates, and then translating the mouse coordinates back.

This simply isn't working - mouse coordinates are not being transformed as expected (that is, not within the bounds of the original rectangle when clicking within the visible bounds of the rotated rectangle), and testing against the rectangle's bounds is failing. Detection of mouse clicks works only within the centre-most area of the rectangle. Please see the code snippet below and tell me if you can see what's wrong here.

 // Our origin of rotation is the center of the rectangle
 // Our rectangle has its upper-left corner defined by x,y, its width
 // defined in w, height in h, and rotation(in radians) in r.  
var originX = this.x + this.w/2, originY = this.y + this.h/2, r = -this.r;

 // Perform origin translation
mouseX -= originX, mouseY -= originY;
// Rotate mouse coordinates by opposite of rectangle rotation
mouseX = mouseX * Math.cos(r) - mouseY * Math.sin(r);
mouseY = mouseY * Math.cos(r) + mouseX * Math.sin(r);
// Reverse translation
mouseX += originX, mouseY += originY;

// Bounds Check
if ((this.x <= mouseX) && (this.x + this.w >= mouseX) && (this.y <= mouseY) && (this.y + this.h >= mouseY)){
    return true;
}

Answer 1

After some further work, came to the following solution, which I thought I'd transcribe here for anyone who might need it in the future:

// translate mouse point values to origin
    var dx = mouseX - originX, dy = mouseY - originY;
    // distance between the point and the center of the rectangle
    var h1 = Math.sqrt(dx*dx + dy*dy);
    var currA = Math.atan2(dy,dx);
    // Angle of point rotated around origin of rectangle in opposition
    var newA = currA - this.r;
    // New position of mouse point when rotated
    var x2 = Math.cos(newA) * h1;
    var y2 = Math.sin(newA) * h1;
    // Check relative to center of rectangle
    if (x2 > -0.5 * this.w && x2 < 0.5 * this.w && y2 > -0.5 * this.h && y2 < 0.5 * this.h){
        return true;
    }