[英]What is the MathNet equivalent of MATLAB solve C = A \ B
I've recently begun using MathNet to implement our linear algebra, however I'm having some trouble translation MATLAB functions to MathNet. 我最近开始使用MathNet来实现我们的线性代数,但是我在将MATLAB函数转换为MathNet时遇到了一些麻烦。
In MATLAB I often use the simple solve using the backslash operator: 在MATLAB中,我经常使用反斜杠运算符来简单求解:
C = A \\ B C = A \\ B
What is the equivalent of this in MathNet? MathNet中的等价物是什么?
I get the same results in a small matrix using C = Inv(A) * B, but I don't know if the result is as precise. 我使用C = Inv(A)* B在小矩阵中得到相同的结果,但我不知道结果是否精确。
var C = A.QR().Solve(B);
(using QR decomposition) (使用QR分解)
For square matrices also: var C = A.LU().Solve(B);
对于平方矩阵,: var C = A.LU().Solve(B);
(using LU decomposition) (使用LU分解)
I don't think MathNet has any "equivalent" of Matlab's backslash operator. 我不认为MathNet有任何“等效”的Matlab反斜杠运算符。 See this site for some info on how Matlab's backslash works: Matlab manual on mldivide() . 有关Matlab反斜杠如何工作的一些信息,请访问此站点: mldivide()上的Matlab手册 。 I guess you could look at some of the solve methods, like QRSolve, but I don't think they will be as easy to use... 我想你可以看看一些解决方法,比如QRSolve,但我认为它们不会那么容易使用......
What do you mean by "precise"? 你说“精确”是什么意思? Are you asking if MathNet's inv() does exact inversion of a matrix, or are you simply asking if you could calculate C as Inv(A)*(B)? 您是在询问MathNet的inv()是否对矩阵进行了精确反演,或者您只是在询问是否可以将C计算为Inv(A)*(B)?
If you are asking the later, yes, for square matrices Matlab's backslash is roughly the same as Inv(A)*(B). 如果你问的是后者,是的,对于方形矩阵,Matlab的反斜杠与Inv(A)*(B)大致相同。
With the tests I've made using Matlab and Math.Net Numerics: 通过我使用Matlab和Math.Net Numerics进行的测试:
Matrix A Vector B 矩阵A矢量B.
Matlab: A \\ B Math.Net Numerics: A.QR().Solve(B) Matlab:A \\ B Math.Net数字:A.QR()。解决(B)
Both give the same results (in my case). 两者都给出了相同的结果(在我的例子中)。 I think it will work with B being a Matrix also. 我认为这也适用于B也是一个矩阵。
如果您使用ILNumerics.Net库 ,您可以尝试ILMath.linsolve(A, B);
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