[英]How to use variable when setting makeprg in vim?
I am creating a method called SetLaunchingComponent which is used to set the makeprg with the variable passed in.This is how the script look like now. 我正在创建一个名为SetLaunchingComponent的方法,该方法用于通过传入的变量来设置makeprg。这就是脚本现在的样子。
function! SetLaunchingComponent(path)
set makeprg=$path
endfunction
Obviously the function isn't working as i wished. 显然,该功能无法正常运行。 As vim resolve the path environment as the system variable but not a:path.
在vim中,将路径环境解析为系统变量,而不是a:path。 So what should i do?
所以我该怎么做?
要设置一个选项,您应该使用以下语法:
let &makeprg=a:path
command! -n=1 SL call SetLanuchingComponent(<arg>)
这将使您易于使用该功能。
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