遍历 Java 字符串行的最佳方法是什么？

Question

Currently I'm using something like:

String[]lines = textContent.split(System.getProperty("line.separator"));
for(String tmpLine : lines){
   //do something
}

I'm not very glad of this method because it create an heavy array (let say textContent can contain a book).

Is there any better solution to iterate over the lines of a String ?

Answer 1

You could use :

BufferedReader bufReader = new BufferedReader(new StringReader(textContent));

And use the readLine() method :

String line=null;
while( (line=bufReader.readLine()) != null )
{

}

Answer 2

To add the Java 8 way to this question:

Arrays.stream(content.split("\\r?\\n")).forEach(line -> /*do something */)

Of curse you can also use System.lineSeparator() to split if you are sure that the file is comming from the same plattform as the vm runs on.

Or even better use the stream api even more agressiv with filter, map and collect:

String result = Arrays.stream(content.split(System.lineSeparator()))
                     .filter(/* filter for lines you are interested in*/)
                     .map(/*convert string*/)
                     .collect(Collectors.joining(";"));

Answer 3

I believe you have a better API available starting with Java-11 where you can do the same using the String.lines() API which returns the stream of strings extracted from this string partitioned by line terminators.

public Stream<String> lines()

Usage of the same could be:-

Stream<String> linesFromString = textContent.lines();
linesFromString.forEach(l -> {  //do sth });

Important API Note :-

@implNote This method provides better performance than
          split("\R") by supplying elements lazily and
          by faster search of new line terminators.

Answer 4

You could use String.indexOf()/String.substring()

String separator = System.getProperty("line.separator");
int index = textContent.indexOf(separator);

while (index > 0)
{
  int nextIndex = textContent.indexOf(separator, index + separator.length());
  String line = textContent.substring(index + separator.length(), nextIndex);

  // do something with line.
}

Answer 5

Scanner

What about the java.util.Scanner class added in Java 1.5?

In summary:

A simple text scanner which can parse primitive types and strings using regular expressions.

A Scanner breaks its input into tokens using a delimiter pattern, which by default matches whitespace. The resulting tokens may then be converted into values of different types using the various next methods.

and of note for your scenario:

The scanner can also use delimiters other than whitespace. This example reads several items in from a string:

 String input = "1 fish 2 fish red fish blue fish"; Scanner s = new Scanner(input).useDelimiter("\\\\s*fish\\\\s*"); System.out.println(s.nextInt()); System.out.println(s.nextInt()); System.out.println(s.next()); System.out.println(s.next()); s.close();

Answer 6

Guava's Splitter works well. Especially as you can remove blank lines

Splitter splitter = Splitter.on(System.getProperty("line.separator"))
                            .trimResults()
                            .omitEmptyStrings();
for (String line : splitter.split(input)){
   // do work here
}

Answer 7

You can actually wrangle Scanner to allow you to use a normal for loop:

import java.util.Scanner;
public class IterateLines {
    public static void main(String[] args) {
        Iterable<String> sc = () ->
            new Scanner("foo bar\nbaz\n").useDelimiter("\n");
        for (String line: sc) {
            System.out.println(line);
        }
    }
}

gives us:

$ javac IterateLines.java && java IterateLines 
foo bar
baz

Answer 8

If you are using Java 1.8 (or Android) then try this:

new BufferedReader(new StringReader(str)).lines().forEachOrdered((line) -> {
    // process each line as you like
});

Docs state

The Stream is lazily populated, ie, read only occurs during the terminal stream operation.

Which means this runs quicker than other solutions that first generate a massive array of Strings before iteration can begin.

If you are using Java 11 or later then the answer @Naman gave recommending String#lines() method is even cleaner and fast as well, see https://stackoverflow.com/a/50631579/215266

Answer 9

结合java.io.StringReader和java.io.LineNumberReader

Answer 10

use BufferedReader with StringReader argument. BufferedReader has a method readLine() so you can read your string line by line.

    StringReader reader = new StringReader(myBigTextString);
    BufferedReader br = new BufferedReader(reader);
    String line;
    while((line=br.readLine())!=null)
    {
        //do what you want
    }

Answer 11

You could use:

Scanner scanner = new Scanner(yourString);
while (scanner.hasNextLine()) {
String line = scanner.nextLine();
          
// process the line
          
}
scanner.close();