关闭主JFrame

Question

I have a main jFrame with the help of which i press button and open new JFrames but the problem is that when i open other JFrame the previous ones still remains there where as what i want is that when i press next button then i move forward to the new JFrame (the previous one should not be there) and when i press previous button i move back to the previous JFrame.

I know there are functions of dispose,they do well like jframe1.dispose() but i dont get it how to hide the very first JFrame whose code in the main is written like this

    public static void main(String args[]) {


    java.awt.EventQueue.invokeLater(new Runnable() {
        public void run() 
          {          
           new GraphicalInterface().setVisible(true);
          }
       });
     }

how do i set this as .setVisible(false) in the button code?

Answer 1

You need to retain a reference to the JFrame , so you can set it's visibility later.

private JFrame myFrame;

public void run() {
  myFrame = new GUI();
  myFrame.setVisible(true);
}

public void hide() {
  myFrame.setVisible(false);
}

Note that a JFrame is a top-level container, you are only really supposed to have one per application. It may be better if instead of using multiple JFrame s you use just one, and swap in various JPanel s instead.

Answer 2

It would safe resources if you keep just one frame and set a new panel as content.

Your question was how to handle the reference to the frame? Please provide the code where the next frame is created.

Answer 3

You could assign your GUI (extends JFrame I suppose) to a variable and call .setVisible(false) on that object. Since your object from the code above is more or less anonymous, you won't have access on that.

You could also check this .