如何在iOS5中替换此语句

Question

When i write ' stringWithContentsOfURL' i am getting error that 'stringWithContentsOfURL is Deprecated'.

    -(CLLocationCoordinate2D) addressLocation 
{
        NSString *urlString = [NSString stringWithFormat:@"http://maps.google.com/maps/geo?q=%@&output=csv", 
      [addressField.text stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
        NSString *locationString = [NSString stringWithContentsOfURL:[NSURL URLWithString:urlString]];
        NSArray *listItems = [locationString componentsSeparatedByString:@","];

        double latitude = 0.0;
        double longitude = 0.0;

        if([listItems count] >= 4 && [[listItems objectAtIndex:0] isEqualToString:@"200"]) {
            latitude = [[listItems objectAtIndex:2] doubleValue];
            longitude = [[listItems objectAtIndex:3] doubleValue];
        }
        else {
            //Show error
        }
        CLLocationCoordinate2D location;
        location.latitude = latitude;
        location.longitude = longitude;

        return location;
    }

How can i replace this line. Thanks!

NSString *locationString = [NSString stringWithContentsOfURL:[NSURL URLWithString:urlString]];

Answer 1

It has been replaced with

stringWithContentsOfURL:encoding:error: 

or

stringWithContentsOfURL:usedEncoding:error:

Example code

NSError* error = nil;
NSString* locationString = [NSString stringWithContentsOfURL:[NSURL URLWithString:urlString] encoding:NSASCIIStringEncoding error:&error];

Answer 2

Check the documentation for stringWithContentsOfURL. In the NSString documentation it tells you exactly what methods are used to replace that deprecated one, and its good to know how to do as checking the docs for this sort of stuff is something you'll do frequently.